Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises - Page 112: 58

Answer

$(1+3i)(2-5i)=17+i$

Work Step by Step

$(1+3i)(2-5i)$ Evaluate the product by multiplying each term of the first factor by every term of the second factor: $(1+3i)(2-5i)=2-5i+6i-15i^{2}=...$ Substitute $i^{2}$ by $-1$ and simplify: $...=2-5i+6i-15(-1)=2+i+15=17+i$
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