Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set: 73

Answer

$2x$

Work Step by Step

Using the properties of radicals and exponents, the given expression simplifies to $\sqrt[5]{\dfrac{64x^6}{2x}} \\=\sqrt[5]{32x^{6-1}} \\=\sqrt[5]{32x^5} \\=\sqrt[5]{2^5x^5} \\=\sqrt[5]{(2x)^5} \\=2x.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.