Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set: 40

Answer

$\sqrt{7x}$

Work Step by Step

Simplify each radical to obtain $\sqrt{9(7x)} - \sqrt{4(7x)} \\=\sqrt{3^2(7x)}-\sqrt{2^2(7x)} \\=3\sqrt{7x}-2\sqrt{7x}.$ RECALL: The distributive property states that for any real numbers a, b, and c, $(ac-bc)=(a-b)c.$ Use the rule above to obtain $(3-2)\sqrt{7x} \\=1\cdot \sqrt{7x} \\=\sqrt{7x}$
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