Answer
$\dfrac{\sqrt{21}}{3}$
Work Step by Step
RECALL:
(i) For any nonnegative real number $a$, $\sqrt{a} \cdot \sqrt{a} = a$.
(ii) For any nonnegative real numbers a and b, $\sqrt{a}\cdot\sqrt{b} = \sqrt{ab}$.
Rationalize the denominator by multiplying $\sqrt{3}$ to the numerator and the denominator. Then, use the rules above to obtain
$\dfrac{\sqrt{7}}{\sqrt{3}} \cdot \dfrac{\sqrt{3}}{\sqrt{3}}
\\=\dfrac{\sqrt{21}}{3}.$
