Answer
$2\sqrt[3]{6}$
Work Step by Step
RECALL:
For any real numbers $a$ and $b$,
$\sqrt[3]{a} \cdot \sqrt[3]{b} = \sqrt[3]{ab}.$
Use the rule above to obtain
$\sqrt[3]{12(3)}
\\=\sqrt[3]{48}.$
Factor the radicand so that one factor is a perfect cube to obtain
$\sqrt[3]{8(6)}
\\=\sqrt[3]{2^3(6)}.$
Simplify to obtain
$2\sqrt[3]{6}.$
