Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 3 - Section 3.3 - Solving Linear Equations in One Variable - Exercise Set - Page 188: 8

Answer

The solution is -80

Work Step by Step

57y +140=54y-100 Subtract 54y to both sides 57y +140 -54y=54y-100-54y Simplify 3y +140=-100 Subtract 140 from both sides 3y +140 -140=-100 -140 Simplify 3y=-240 Divide both sides by 3 $\frac{3y}{3}$=$\frac{-240}{3}$ y=-80 The solution is -80 Check 57y +140=54y-100 57(-80)+140=54(-80)-100 Multiply -4560 +140 =-4320 -100 -4420=-4420
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