Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 3 - Section 3.3 - Solving Linear Equations in One Variable - Exercise Set - Page 188: 11

Answer

$40+4y-16=13y-12-3y$ $y=6$

Work Step by Step

Simplify and isolate the variables. $13y-12-3y=40+4y-16$ Subtract 3y $10y-12=40+4y-16$ Subtract 16. $10y-12=4y+24$ Move terms $6y-12=24$ Add 12 $6y=36$ Divide by 6 $y=6$
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