Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 3 - Section 3.3 - Solving Linear Equations in One Variable - Exercise Set: 17

Answer

The solution is 0

Work Step by Step

2(y-3) =y-6 Apply the distributive property 2y-2$\times$ 3 =y-6 2y-6=y-6 Subtract -6 from both sides 2y-6+6=y-6 +6 2y=y Subtract y from both sides 2y-y=y-y y=0 The solution is -0 Check 2(y-3) =y-6 2(-0-3) =0-6 2(-3)=-6 -6=-6
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