Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 3 - Section 3.3 - Solving Linear Equations in One Variable - Exercise Set - Page 188: 3

Answer

The solution is -3

Work Step by Step

10x+15 =6x+3 Subtact 15 from both sides 7 10x+15 -15 =6x+3 -15 Simplify 10x =6x - 12 Subtract 6x from both sides 10x -6x =6x - 12 -6x Simplify 4x = -12 Divide both sides by 4 $\frac{4x}{4}$ = $\frac{-12}{4}$ x = -3 The solution is -3 Check 10x+15 =6x+3 10(-3)+15 =6(-3)+3 Multiply -30 +15= -18 +3 -15=-15
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