Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2: 79

Answer

The solution to this equation is all real numbers. Using set notation: {x|x is an element of the Real Numbers}

Work Step by Step

4x + 1 - 5x = 5 - (x + 4) Solving the equation, we start by using the distributive property to distribute a -1 across the parentheses. 4x + 1 - 5x = 5 -x - 4 Next, we can regroup each side of the equation so that like terms are together. 4x - 5x + 1 = 5 - 4 - x Then, combine like terms: -x + 1 = 1 - x Add x to both sides: -x + x + 1 = 1 - x + x 1 = 1 Since our variable term completely cancelled out, and our numbers in our last line show an equality, the solution is: ALL REAL NUMBERS
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