Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2: 21

Answer

{$\frac{7}{5}$}

Work Step by Step

9(5x -2) = 45 Step 1 : Use distributive property 9.(5x) - 9.2 =45 Step 2: Multiply 9.(5x) =45x , 9.2 = 1 45x - 18 = 45 Step 1: Add 18 on both the sides 45x - 18 + 18 = 45 + 18 Step 2: Simplify 45x = 63 Step 3: Divide both the sides by 45 $\frac{45x}{45}$ = $\frac{63}{45}$ Step 4: Simplify x = $\frac{7}{5}$ Now we check the proposed solution, $\frac{7}{5}$, by replacing x with $\frac{7}{5}$ in the original equation. Step 1: the original equation 9(5x-2) = 45 Step2: Substitute $\frac{7}{5}$ for x 9(5($\frac{7}{5}$) -2) = 45 Step 3: Multiply 5($\frac{7}{5}$) = 7 9(7 -2) = 45 Step 4: Solve parenthesis 7-2 = 5 9(5) =54 Step 5: Multiply 9(5) = 45 45 = 45 Since the check results in true statement, we conclude that the solution set of the given equation is {$\frac{7}{5}$}
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