Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2 - Page 362: 6

Answer

{15}.

Work Step by Step

$\frac{x}{5}$ = 3 Step 1: Multiply both the sides by 5 $\frac{x}{5}$ x 5 = 3x5 Step 2: Simplify x= 15 Now we check the proposed solution, 15, by replacing x with 15 in the original equation. Step 1: the original equation $\frac{x}{5}$ = 3 Step2: Substitute 15 for x $\frac{15}{5}$ = 3 Step 3: Solve $\frac{15}{5}$ =3 3=3 Since the check results in true statement, we conclude that the solution set of the given equation is {15}.
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