Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2: 27

Answer

{-3}

Work Step by Step

8x - 2 = 7x - 5 Step 1 : Collect variable terms on one side and constants on the other side. subtract 7x from both the sides 8x - 2 - 7x = 7x - 5 -7x Simplify x - 2 = -5 Add 2 on both the sides x -2 + 2 = -5 + 2 Simplify x = -3 Now we check the proposed solution,-3 , by replacing x with -3 in the original equation. Step 1: the original equation 8x - 2 = 7x - 5 Step2: Substitute -3 for x 8.(-3) - 2 = 7.(-3) - 5 Step 3: Multiply 8.(-3) = -24, 7.(-3) = -21 -24 - 2 = -21 -5 Step 4: Solve -26 = -26 Since the check results in true statement, we conclude that the solution set of the given equation is {-3}
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