Answer
$-\frac{3\sqrt3}{2}$
Work Step by Step
Simplify each radical when needed to obtain:
$=\frac{1}{4}\sqrt{4(3)} -\frac{1}{2}\sqrt{16(3)}
\\=\frac{1}{4}(2)\sqrt{3} -\frac{1}{2}(4)\sqrt{3}
\\=\frac{1}{2}\sqrt{3}-2\sqrt{3}
\\=(\frac{1}{2} - 2)\sqrt{3}
\\=-\frac{3}{2}\sqrt{3}$
