Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.4 The Irrational Numbers - Exercise Set 5.4 - Page 296: 49

Answer

$2\sqrt2$

Work Step by Step

Simplify each radical when needed to obtain: $=\sqrt{25(2)} - \sqrt{9(2)} \\=5\sqrt{2} - 3\sqrt{2} \\=(5-3)\sqrt{2} \\=2\sqrt{2}$
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