Answer
$-4\sqrt3$
Work Step by Step
Use the quotient rule $\dfrac{\sqrt{a}}{\sqrt{b}}=\sqrt{\dfrac{a}{b}}$, where $a$ and $b$ are nonnegative numbers and $b\ne 0$ to obtain:
$=-\sqrt{\dfrac{96}{2}}
\\=-\sqrt{48}
\\=-\sqrt{16(3)}
\\=-4\sqrt3$
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 5 - Number Theory and the Real Number System - 5.4 The Irrational Numbers - Exercise Set 5.4 - Page 296: 37
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