Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.4 The Irrational Numbers - Exercise Set 5.4: 37

Answer

$-4\sqrt3$

Work Step by Step

Use the quotient rule $\dfrac{\sqrt{a}}{\sqrt{b}}=\sqrt{\dfrac{a}{b}}$, where $a$ and $b$ are nonnegative numbers and $b\ne 0$ to obtain: $=-\sqrt{\dfrac{96}{2}} \\=-\sqrt{48} \\=-\sqrt{16(3)} \\=-4\sqrt3$
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