Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.6 Events Involving Not and Or; Odds - Exercise Set 11.6: 52

Answer

$\frac{69}{142}$

Work Step by Step

The probability that an event E will not occur is equal to 1 minus the probability that it will occur. P(not E)= 1 - P(E) E: Is in the Army or is a woman. A = Neither in Army nor woman. P(is in the Army or is a woman) = 1 - P(Neither in Army nor woman) P(Neither in Army nor woman) = $\frac{730000}{1420000}$ = $\frac{73}{142}$ P(is in the Army or is a woman) = 1 - $\frac{73}{142}$ = $\frac{142 - 73}{142}$ = $\frac{69}{142}$
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