Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.6 Events Involving Not and Or; Odds - Exercise Set 11.6 - Page 736: 90

Answer

$\frac{193}{463}$

Work Step by Step

The odds for $E$: $\frac{P(E)}{P(\text{not E})}$. The probability for $E$: $\frac{P(E)}{P(\text{not E})+P(E)}$. Hence here the probability is: $\frac{193}{270+193}=\frac{193}{463}$
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