Answer
$\frac{55}{16}$ , $\frac{16}{55}$
Work Step by Step
The odds in favor of E are found by taking the probability that E will occur
and dividing it by the probability that E will not occur.
Odds in Favor = $\frac{P(E)}{P(not E)}$
We are asked to find the odds in favor and the odds against a person being in the Navy.
P(E)= $\frac{320000}{1420000}$ = $\frac{32}{142}$
P(not E) = 1 - P(E)
= 1 - $\frac{32}{142}$
=$\frac{142 - 32}{142}$
= $\frac{110}{142}$ = $\frac{55}{71}$
Odds in Favor = $\frac{\frac{16}{71}}{\frac{55}{71}}$ = $\frac{16}{55}$
The odds against E are found by taking the probability that E will not occur
and dividing by the probability that E will occur.
Odds against E = $\frac{P(not E)}{P(E)}$
Odds against E = $\frac{\frac{55}{71}}{\frac{16}{71}}$ = $\frac{55}{16}$
