Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.6 Events Involving Not and Or; Odds - Exercise Set 11.6: 69

Answer

1:1

Work Step by Step

The odds in favor of E are found by taking the probability that E will occur and dividing by the probability that E will not occur. Odds in Favor = $\frac{P(E)}{P(not E)}$ The odds in favor of drawing a red card are: E: {26 red cards} P(E) = $\frac{26}{52}$ = $\frac{1}{2}$ P(not E) = 1 - P(E) = 1 - $\frac{1}{2}$ =$\frac{2-1}{2}$ = $\frac{1}{2}$ Odds in Favor = $\frac{\frac{1}{2}}{\frac{1}{2}}$ = $\frac{1}{1}$
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