Answer
The cost of applying the ceramic tiles in the kitchen and dining is\[\$943.25\].
Work Step by Step
To calculate the cost of installing ceramic tiles in the kitchen and dining floor, it is required the compute the area of the kitchen and dining.
Compute the area of the dining as follows:
\[\begin{align}
& {{A}_{1}}=lb \\
& =10\text{ ft}\times 14\text{ ft} \\
& =140\text{ ft}{{\text{.}}^{\text{2}}}
\end{align}\]
Compute the area of the kitchen as follows:
\[\begin{align}
& {{A}_{2}}=lb \\
& =12\text{ ft}\times 14\text{ ft} \\
& =168\text{ ft}{{\text{.}}^{\text{2}}}
\end{align}\]
Compute the total area of kitchen and dining as follows:
\[\begin{align}
& \text{Total area}={{A}_{1}}+{{A}_{2}} \\
& =140\text{ f}{{\text{t}}^{\text{2}}}+168\text{ f}{{\text{t}}^{\text{2}}} \\
& =308\text{ f}{{\text{t}}^{\text{2}}}
\end{align}\]
It is known that\[\text{1 f}{{\text{t}}^{2}}=\frac{1}{9}\text{ y}{{\text{d}}^{2}}\], convert total area into square yard as follows:
\[\begin{align}
& \text{308 f}{{\text{t}}^{2}}=308\text{ f}{{\text{t}}^{2}}\times \frac{1\text{ y}{{\text{d}}^{2}}}{9\text{f}{{\text{t}}^{2}}} \\
& =\frac{308}{9}\text{y}{{\text{d}}^{2}} \\
& =34.22\text{ y}{{\text{d}}^{2}} \\
& =35\text{ y}{{\text{d}}^{2}}
\end{align}\]
Compute the cost of applying the tiles as follows:
\[\begin{align}
& \text{Cost}=\$26.95\times35\text{y}{{\text{d}}^{2}}\\&=\$943.25\end{align}\]
Hence, the cost of applying the ceramic tiles in the kitchen and dining is\[\$943.25\].
