Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 10 - Geometry - 10.4 Area and Circumference - Exercise Set 10.4 - Page 649: 45

Answer

The cost of carpeting the bedrooms is\[\$933.40\].

Work Step by Step

To calculate the cost of carpeting the three rooms, we will first find the area of the three bedrooms. Compute the area of the master bedroom as follows: \[\begin{align} & {{A}_{1}}=lb \\ & =14\text{ ft}\times 14\text{ ft} \\ & =196\text{ f}{{\text{t}}^{2}} \end{align}\] Compute the area of the second bedroom as follows: \[\begin{align} & {{A}_{2}}=lb \\ & =11\text{ ft}\times 12\text{ ft} \\ & =132\text{ f}{{\text{t}}^{2}} \end{align}\] Compute the area of the second bedroom as follows: \[\begin{align} & {{A}_{3}}=lb \\ & =12\text{ ft}\times 11\text{ ft} \\ & =132\text{ f}{{\text{t}}^{2}} \end{align}\] Compute the total area of all the bedrooms as follows: \[\begin{align} & \text{Total area}={{A}_{1}}+{{A}_{2}}+{{A}_{3}} \\ & =\text{196 f}{{\text{t}}^{2}}+132\text{ f}{{\text{t}}^{2}}+132\text{ f}{{\text{t}}^{2}} \\ & =460\text{ f}{{\text{t}}^{2}} \end{align}\] It is known that\[\text{1 f}{{\text{t}}^{2}}=\frac{1}{9}\text{ y}{{\text{d}}^{2}}\], convert total area into square yard as follows: \[\begin{align} & 460\text{ f}{{\text{t}}^{2}}=460\text{ }f{{t}^{2}}\times \frac{1\text{ y}{{\text{d}}^{2}}}{9f{{t}^{2}}} \\ & =\frac{460}{9}\text{y}{{\text{d}}^{2}} \\ & =51.1\text{ y}{{\text{d}}^{2}} \\ & \simeq 52\text{ y}{{\text{d}}^{2}} \end{align}\] Compute the cost of carpeting these rooms as follows: \[\begin{align} & \text{Cost}=\$17.95\times52\text{y}{{\text{d}}^{2}}\\&=\$933.40\end{align}\] Hence, the cost of carpeting the bedrooms is\[\$933.40\].
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