University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.3 - Differentiation Rules - Exercises: 37

Answer

$y' = \frac{2}{7}x^{-\frac{5}{7}} + ex^{e-1}$

Work Step by Step

$y =\sqrt[7]( x^{2}) + x^{e}$ $y = x^{\frac{2}{7}} + x^{e}$ $y' = \frac{2}{7}x^{-\frac{5}{7}} + ex^{e-1}$
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