University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.3 - Differentiation Rules - Exercises - Page 136: 33

Answer

$y = \frac{9}{4}x^{\frac{5}{4}} -2e^{-2x}$

Work Step by Step

$y = x^{\frac{9}{4}}+ e^{-2x}$ $y = \frac{9}{4}x^{\frac{5}{4}} -2e^{-2x}$
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