University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.3 - Differentiation Rules - Exercises - Page 136: 32

Answer

$w' = e^{-r}(1-r)$

Work Step by Step

$w = re^{-r}$ $w' = -re^{-r} + e^{-r}$ $w' = e^{-r}(1-r)$
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