Answer
$s' = 2t^{-2}-8t^{-3}$
$s' = -4t^{-3}+ 24t^{-4}$
Work Step by Step
$s= -2t^{-1} + \frac{4}{t^{2}}$
$s' = 2t^{-2}-8t^{-3}$
$s' = -4t^{-3}+ 24t^{-4}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.3 - Differentiation Rules - Exercises - Page 135: 8
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