Answer
$y' = 12x - 10 + 10x^{-3}$
$y'' = 12 -30x^{-4}$
Work Step by Step
$y = 6x^{2} - 10x - 5x^{-2}$
$y' = 12x - 10 + 10x^{-3}$
$y'' = 12 - 0 -30x^{-4}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.3 - Differentiation Rules - Exercises - Page 135: 9
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