Answer
$r' = \frac{-2}{3s^{3}} + \frac{5}{2s^{2}}$
$r''= 2s^{-4} - 5s^{-3}$
Work Step by Step
$r = \frac{1}{3s^{2}}- \frac{5}{2s}$
$r = \frac{s^{-2}}{3} - \frac{5s^{-1}}{2}$
$r' = \frac{-2s^{-3}}{3} + \frac{5s^{-2}}{2}$
$r' = \frac{-2}{3s^{3}} + \frac{5}{2s^{2}}$
$r''= \frac{6s^{-4}}{3} - \frac{10s^{-3}}{2}$
$r''= 2s^{-4} - 5s^{-3}$
