Answer
$w'= -6z^{-3} +z^{-2}$
$w'= 18z^{-4} -2z^{-3}$
Work Step by Step
$w= 3z^{-2} - \frac{1}{z}$
$w'= -6z^{-3} +z^{-2}$
$w'= 18z^{-4} -2z^{-3}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.3 - Differentiation Rules - Exercises - Page 135: 7
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