University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.2 - The Derivative as a Function - Exercises: 8

Answer

$r'(s) = 3s^{2} - 4s$

Work Step by Step

$r(s) = s^{3} -2s^{2} +3$ Therefore, $r'(s) = 3s^{3-1} - 2(2)s^{2-1} +0$ $r'(s) = 3s^{2} - 4s$
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