University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.2 - The Derivative as a Function - Exercises - Page 124: 8

Answer

$r'(s) = 3s^{2} - 4s$

Work Step by Step

$r(s) = s^{3} -2s^{2} +3$ Therefore, $r'(s) = 3s^{3-1} - 2(2)s^{2-1} +0$ $r'(s) = 3s^{2} - 4s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.