## University Calculus: Early Transcendentals (3rd Edition)

$-4$ $-2$ $2$
$F(x)=(x-1)^2+1=x^2-2x+2$, therefore $F'(x)=2x-2+0=2x-2$ Therefore: $F'(-1)=2\times(-1)-2=-4$. $F'(0)=2\times(0)-2=-2$ $F'(2)=2\times(2)-2=2$