Answer
$6$
$0$
$-2$
Work Step by Step
$f(x)=4-x^2$, therefore $f'(x)=0-2x$
$f'(-3)=0-2\times(-3)=6$
$f'(0)=0-2\times(0)=0$
$f'(1)=0-2\times(1)=-2$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.2 - The Derivative as a Function - Exercises - Page 124: 1
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