Answer
$v'(t) = 1+t^{-2}$
Work Step by Step
$v(t) = t - \frac{1}{t}$
Therefore,
$v'(t) = (1)t^{1-1}-(-1)t^{-1-1}$
$v'(t) = 1+t^{-2}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.2 - The Derivative as a Function - Exercises - Page 124: 10
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