Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - Review - Exercises - Page 860: 21

Answer

$(1,4,4)$

Work Step by Step

The parametric equations are: $x=2-t; y=1+3t; z=4t$ $\implies 2x-y+z=2$ $\implies 2(2-t)-(1+3t) +4t=2$ $\implies t=1$ Plug $t=1$ into the parametric equations $x=2-t; y=1+3t; z=4t$ We have: $x=2-1; y=1+3(1); z=4(1)$ This implies that $(x,y,z)=(1,4,4)$
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