Answer
$x=1+3t,y=2t,z=−1+t$
Work Step by Step
Given: $x=4+3t,y=2t,z=−2+t$
The direction of the vectors is $<3,2,1>$
Formula for a line$ r=r0+tv $
where$ r0$ is the starting point vector and $v$ is the direction vector.
$r=<1,0,−1>+t<3,2,1> $
Therefore, the parametric equations of the line are:
$x=1+3t,y=2t,z=−1+t$
