Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - Review - Exercises - Page 860: 15

Answer

$x=4-3t,y=-1+2t,z= 2+3t$

Work Step by Step

Given: $A(4,-1,2), B(1,1,5)$ The direction of the vectors is $\lt-3,2,3 \gt$ Formula for a line $r=r_{0}+tv$ where $r_{0}$ is the starting point vector and $v$ is the direction vector. $r=\lt 4,-1,2\gt+t \lt -3,2,3\gt$ Therefore, the parametric equations of the line are: $x=4-3t,y=-1+2t,z= 2+3t$
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