Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - Review - Exercises - Page 860: 23

Answer

Skew

Work Step by Step

Write the parametric equations as follows: $x=1+2t; y=2+3t; z=3+4t$ $t=\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{4}$ and $x=-1+6s; y=3-s; z=-5+2s$ and $s=\dfrac{x+1}{6}=\dfrac{y-3}{-1}=\dfrac{z+5}{2}$ Now, we will set the equations equal to each other. So, $s=\dfrac{2}{5}; t=-1+(3)(\dfrac{2}{5})=\dfrac{1}{5}$ Next, $3+(4) (\dfrac{1}{5})=-5+(2)(\dfrac{2}{5})$ or, $ \dfrac{19}{5} \ne -\dfrac{21}{5}$ We see that the lines do not intersect, so they are skew.
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