Answer
$\dfrac{13}{5}$
Work Step by Step
Scalar projection distance formula: $\dfrac{|ax_1+by_1+c|}{\sqrt {a^2+b^2}}$
Distance from the point $(-2,3)$ to the line $3x-4y+5=0$
Thus,
$\dfrac{|ax_1+by_1+c|}{\sqrt {a^2+b^2}}=\dfrac{|3(-2)+-4(3)+5|}{\sqrt {3^2+(-4)^2}}$
$=\dfrac{|-6-12+5|}{\sqrt {9+16}}$
$=\dfrac{13}{5}$
