Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.3 Exercises - Page 831: 43

Answer

$\frac{1}{\sqrt {21}}$,$\lt\frac{2}{21}, \frac{-1}{21},\frac{4}{21}\gt$

Work Step by Step

Given: $a=\lt2,-1,4\gt$ , $b=\lt0,1,\frac{1}{2}\gt$ Scalar Projection $b$ onto $a$ can be calculated as follows: $\frac{a \times b }{|a|}=\frac{(2 \times 0)+( -1 \times 1)+(4 \times \frac{1}{2})}{\sqrt {{(2)^{2}+(-1)^{2}}+(4)^{2}}}$ $=\frac{0-1+2}{\sqrt {21}}$ $=\frac{1}{\sqrt {21}}$ Vector Projection $b$ onto $a$ can be calculated as follows: $\frac{a \times b }{|a|^{2}}\times a=\frac{1}{21}\lt2,-1,4\gt$ $=\lt\frac{2}{21}, \frac{-1}{21},\frac{4}{21}\gt$ Hence, Scalar Projection $b$ onto $a$ =$\frac{1}{\sqrt {21}}$, Vector Projection $b$ onto $a$=$\lt\frac{2}{21}, \frac{-1}{21},\frac{4}{21}\gt$
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