Chapter 12 - Vectors and the Geometry of Space - 12.3 Exercises - Page 831: 47

$ \lt 0,0, -2\sqrt {10} \gt $

$comp_ab=\frac {a \cdot b}{|a|}=2$ $\frac{3x-z}{\sqrt {10}}=2$ $3x-z = 2\sqrt {10}$ Let $x=0,y-0$ then $3(0)-z=2\sqrt {10}$ $z= -2\sqrt {10}$ Hence, one possible solution is: $ \lt 0,0, -2\sqrt {10} \gt $