Answer
$\begin{array}{|c|r|r|r|r|r|r|r|}
\hline
x & -3 & -2 & -1 & 0 & 1 & 2 & 3 \\
\hline
f(x) &64 & 16 & 4 & 1 & 1/4 & 1/16 & 1/64 \\
\hline
\end{array}$
Technology formula:$\quad $ (1/4)^x$ \quad$ or$ \quad $4^(-x)
Work Step by Step
$4^{-x}=(4^{-})^{x}=(\displaystyle \frac{1}{4})^{x}$,
Technology formula:$\quad $ (1/4)^x$ \quad$ or$ \quad $4^(-x)
$f(-3)=(\displaystyle \frac{1}{4})^{-3}=4^{3}=64\qquad $tech: (1/4)^(-3)
$f(-2)=(\displaystyle \frac{1}{4})^{-2}=4^{2}=16 \qquad $tech: (1/4)^(-2)
$f(-1)=(\displaystyle \frac{1}{4})^{-1}=4^{1}=4 \qquad $tech: (1/4)^(-1)
$f(0)=(\displaystyle \frac{1}{4})^{0}=1\qquad $tech: (1/4)^0
$f(1)=(\displaystyle \frac{1}{4})^{1}=\frac{1}{4}\qquad $tech: (1/4)^1
$f(2)=(\displaystyle \frac{1}{4})^{2}=\frac{1}{16}\qquad $tech: (1/4)^2
$f(3)=(\displaystyle \frac{1}{4})^{3}=\frac{1}{64}\qquad $tech: (1/4)^3
