Answer
$\begin{array}{|c|r|r|r|r|r|r|r|}
\hline
x & -3 & -2 & -1 & 0 & 1 & 2 & 3 \\
\hline
f(x) &1/4 & 1/2 & 1 & 2 & 4 & 8 & 16 \\
\hline
\end{array}$
Technology formula:$\quad $2*(2^x)$ \quad$ or$ \quad $2*2^x
Work Step by Step
Technology formula:$\quad $2*(2^x)$ \quad$ or$ \quad $2*2^x.
PEMDAS (acronym for order of operations) has exponents before multiplication, so the parentheses are not necessary, although they are not an error.
$f(-3)=2(2^{-3})=\displaystyle \frac{2}{2^{3}}=\frac{2}{8}=\frac{1}{4}\qquad $tech: 2*2^(-3)
$f(-2)=2(2^{-2})=\displaystyle \frac{2}{2^{2}}=\frac{2}{4}=\frac{1}{2}\qquad $tech: 2*2^(-2)
$f(-1)=2(2^{-1})=\displaystyle \frac{2}{2^{1}}=\frac{2}{2}=1\qquad $tech: 2*2^(-1)
$f(0)=2(2^{0})=2(1)=2\qquad $tech: 2*2^0
$f(1)=2(2^{1})=2(2)=4\qquad $tech: 2*2^1
$f(2)=2(2^{2})=2(2^{2})=8\qquad $tech: 2*2^2
$f(3)=2(2^{3})=2(2^{3})=16\qquad $tech: 2*2^3
