Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.2 - Exponential Functions and Models - Exercises - Page 642: 3

Answer

$\begin{array}{|c|r|r|r|r|r|r|r|} \hline x & -3 & -2 & -1 & 0 & 1 & 2 & 3 \\ \hline f(x) &27 & 9 & 3 & 1 & 1/3 & 1/9 & 1/27 \\ \hline \end{array}$ Technology formula:$\quad $ (1/3)^x $\quad$ or$ \quad $3^(-x)

Work Step by Step

$3^{-x}=(3^{-1})^{x}=(1/3)^{x}$, Technology formula:$\quad $ (1/3)^x$ \quad$ or$ \quad $3^(-x) $f(-3)=(\displaystyle \frac{1}{3})^{-3}=3^{3}=27\qquad $tech: (1/3)^(-3) $f(-2)=(\displaystyle \frac{1}{3})^{-2}=3^{2}=9 \qquad $tech: (1/3)^(-2) $f(-1)=(\displaystyle \frac{1}{3})^{-1}=3^{1}=3 \qquad $tech: (1/3)^(-1) $f(0)=(\displaystyle \frac{1}{3})^{0}=1\qquad $tech: (1/3)^0 $f(1)=(\displaystyle \frac{1}{3})^{1}=\frac{1}{3}\qquad $tech: (1/3)^1 $f(2)=(\displaystyle \frac{1}{3})^{2}=\frac{1}{9}\qquad $tech: (1/3)^2 $f(3)=(\displaystyle \frac{1}{3})^{3}=\frac{1}{27}\qquad $tech: (1/3)^3
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