Answer
$\begin{array}{|c|r|r|r|r|r|r|r|}
\hline
x & -3 & -2 & -1 & 0 & 1 & 2 & 3 \\
\hline
r(x) &-\displaystyle \frac{7}{8} & -\displaystyle \frac{3}{4} & -\displaystyle \frac{1}{2} & 0 & 1 & 3 & 7 \\
\hline
\end{array}$
Technology formula:$\quad 2$^$x-1$
Work Step by Step
Technology formula:$\quad 2$^$x-1$
$f(-3)=2^{-3}-1=(\displaystyle \frac{1}{2})^{3}-1=\frac{1}{8}-1=-\frac{7}{8}\qquad $tech:$\qquad 2$^$(-3)-1$
$f(-2)=2^{-2}-1=(\displaystyle \frac{1}{2})^{2}-1=\frac{1}{4}-1=-\frac{3}{4}\qquad $tech:$ \qquad2$^$(-2)-1$
$f(-1)=2^{-1}-1=(\displaystyle \frac{1}{2})^{1}-1=\frac{1}{2}-1=-\frac{1}{2}\qquad $tech:$\qquad 2$^$(-1)-1$
$f(0)=2^{0}-1=1-1=0 \qquad $tech:$\qquad 2$^$0-1$
$f(1)=2^{1}-1=2-1=1 \qquad $tech:$\qquad2$^$1-1$
$f(2)=2^{2}-1=4-1=3 \qquad $tech:$ \qquad2$^$2-1$
$f(3)=2^{3}-1=8-1=7 \qquad $tech:$\qquad 2$^$3-1$
