Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises: 13

Answer

$5\sqrt[3]{2}$

Work Step by Step

Simplify each radical, when needed, to have: $=\sqrt[3]{2}-\sqrt[3]{8(2)} + 2\sqrt[3]{27(2)} \\= \sqrt[3]{2} -2\sqrt[3]{2} + 2\cdot3\sqrt[3]{2} \\= \sqrt[3]{2} -2\sqrt[3]{2} + 6\sqrt[3]{2}$ Combine like terms to have: $=(1-2+6)\sqrt[3]{2} \\=5\sqrt[3]{2}$
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