Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises: 12

Answer

$-2\sqrt{7}$

Work Step by Step

Simplify each radical, when needed, to have: $=3\sqrt{4(7)}-4\sqrt{9(7)} + \sqrt{16(7)} \\=3 \cdot 2\sqrt{7} -4\cdot3\sqrt{7} + 4\sqrt{7} \\=6\sqrt{7}-12\sqrt{7} + 4\sqrt{7}$ Combine like terms to have: $=(6-12+4)\sqrt{7} \\=-2\sqrt{7}$
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