Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises: 30

Answer

$\sqrt2$

Work Step by Step

Rationalize the denominator by multiplying $\sqrt{2}$ to both the numerator and the denominator to have: $=\dfrac{4}{\sqrt{8}} \cdot \dfrac{\sqrt{2}}{\sqrt{2}} \\=\dfrac{4\sqrt{2}}{\sqrt{16}} \\=\dfrac{4\sqrt2}{4}$ Cancel the common factor $4$ to have: $=\sqrt2$
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