Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises: 14

Answer

$3\sqrt[3]{5}$

Work Step by Step

Simplify each radical, when needed, to have: $=2\sqrt[3]{5}-4\sqrt[3]{8(5)} + 3\sqrt[3]{27(5)} \\= 2\sqrt[3]{5} -4\cdot2\sqrt[3]{5} + 3\cdot3\sqrt[3]{5} \\= 2\sqrt[3]{5} -8\sqrt[3]{5} + 9\sqrt[3]{5}$ Combine like terms to have: $=(2-8+9)\sqrt[3]{5} \\=3\sqrt[3]{5}$
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