Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises: 6

Answer

$4y^2\sqrt{2y}$

Work Step by Step

$\sqrt{32y^5} \\= \sqrt{16(y^4)(2y)} \\=4y^2\sqrt{2y}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.