Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises - Page R-28: 9

Answer

$7\sqrt{2}$

Work Step by Step

Simplify each radical, when needed, to have: $=7\sqrt{2}-8\sqrt{9(2)} + 4\sqrt{36(2)} \\=7\sqrt{2} - 8\cdot 3\sqrt{2} + 4\cdot 6\sqrt{2} \\=7\sqrt{2} - 24\sqrt{2} + 24\sqrt{2}$ Combine like terms to have: $=(7-24+24)\sqrt{2} \\=7\sqrt{2}$
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